PT is a tangent at the point R on a circle with centre O. SQ is a diameter. Which when produced

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PRT is a tangent to a circle with centre O, at the point R on it. Diameter SQ of the circle is PRT is a tangent to a circle with centre O, at the point R on it. Diameter SQ of the circle is
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In the given figure, PT touches the circle with centre O at point R. Diameter SQ is produced to ... In the given figure, PT touches the circle with centre O at point R. Diameter SQ is produced to ...
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Icse Selina | Exercise 18A Q-21 |ICSE Class 10 Icse Selina | Exercise 18A Q-21 |ICSE Class 10
Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy