AD is perpendicular to the internal bisector of ∠ABC of Δ ABC.DE is drawn through D and parallel

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In triangle ABC AD is angle bisector and BD is perpendicular to AD. DE || AC. Find BE In triangle ABC AD is angle bisector and BD is perpendicular to AD. DE || AC. Find BE
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In Δ ABC, AD is the internal bisector of ∠A, meeting the side BC at D. If BD = 5 cm, In Δ ABC, AD is the internal bisector of ∠A, meeting the side BC at D. If BD = 5 cm,
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