If `I=sum_(k=1)^(98)int_(k)^(k+1)(k+1)/(x(x+1))dx`, then

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If I = Summation from k=1 to 98 Integral of k+1/x(x+1) from k to k+l, then: | JEE Advanced Maths If I = Summation from k=1 to 98 Integral of k+1/x(x+1) from k to k+l, then: | JEE Advanced Maths
Integration JEE Advance 2017 : If 𝐼=∑_(𝑘=1)^98 ∫_𝑘^(𝑘+1) (𝑘+1)/(𝑥(𝑥+1)) 𝑑𝑥,then Integration JEE Advance 2017 : If 𝐼=∑_(𝑘=1)^98 ∫_𝑘^(𝑘+1) (𝑘+1)/(𝑥(𝑥+1)) 𝑑𝑥,then
JEE MAINS 2018 If `Isum_(k=1)^(98)int_k^(k+1)(k+1)/(x(x+1))dx ,t h e n:` `I lt(49)/(50)` (... JEE MAINS 2018 If `Isum_(k=1)^(98)int_k^(k+1)(k+1)/(x(x+1))dx ,t h e n:` `I lt(49)/(50)` (...
∫(x+((x+…)/(1+…)))/(1+((x+…)/(1+…)))dx [1,3] MIT Integration Bee 2024, Qualifying Exam, Question 20. ∫(x+((x+…)/(1+…)))/(1+((x+…)/(1+…)))dx [1,3] MIT Integration Bee 2024, Qualifying Exam, Question 20.
😳 CLEAN BASIC CALCULUS Integrate ∫1/x dx=? #Shorts 😳 CLEAN BASIC CALCULUS Integrate ∫1/x dx=? #Shorts
∆^kf(x)=Summation i=0 to k(-1)^i(k_C_i)f[x+(k-i)h] Or ∆^ky_0=Summation i=0 to k(-1)^i(k_C_i)y_(k-i) ∆^kf(x)=Summation i=0 to k(-1)^i(k_C_i)f[x+(k-i)h] Or ∆^ky_0=Summation i=0 to k(-1)^i(k_C_i)y_(k-i)
Let rk= int_0 to 1 (1-x^7)^k dx/int_0to1 (1-x^7)^k+1 dx ,k€R.Then the value of sum_k=1to10 1/7(rk-1) Let rk= int_0 to 1 (1-x^7)^k dx/int_0to1 (1-x^7)^k+1 dx ,k€R.Then the value of sum_k=1to10 1/7(rk-1)
Inductive Proof Example 4 - Sum of x^k Inductive Proof Example 4 - Sum of x^k