AB is dia of a circle, CD is a chord = radius. AC and BD extended to intersect at E. Find Angle AEB.

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AB is a diameter of the circle, CD is a chord equal to the radius of the circle. Prove that ∠AEB=60° AB is a diameter of the circle, CD is a chord equal to the radius of the circle. Prove that ∠AEB=60°
AB is diameter and CD is equal to the radius of the circle.AC and BD intersect at point E.find AEB AB is diameter and CD is equal to the radius of the circle.AC and BD intersect at point E.find AEB
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