In figure, ABD is a triangle angled at A and AC is perpendicular to BD. Show that: (i)AB²= BC.BD

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In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC. - Teachoo In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC. - Teachoo
1. In figure, ΔABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB2 = BC.BD. 1. In figure, ΔABD is a right triangle, right angled at A and AC ⊥ BD. Prove that AB2 = BC.BD.
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In figure, ABD is a triangle right angled at A and AC ⊥ BD. #cbseclass10maths In figure, ABD is a triangle right angled at A and AC ⊥ BD. #cbseclass10maths
In Figure, ABD is a triangle right angled at A and `A C_|_B D`. Show that (i)`A B^2=B CdotB D` In Figure, ABD is a triangle right angled at A and `A C_|_B D`. Show that (i)`A B^2=B CdotB D`
ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(i) AB2 = BC . BD(ii) AC2 = BC . DC ABD is a right triangle right-angled at A and AC ⊥ BD. Show that(i) AB2 = BC . BD(ii) AC2 = BC . DC
In Fig 6.53 ABD Is A Triangle Right Angled At A And AC Perpendicular To BD Show That (I) AB²=BC.BD In Fig 6.53 ABD Is A Triangle Right Angled At A And AC Perpendicular To BD Show That (I) AB²=BC.BD
AB² = BC.BD AC² = BC.DC AD² = BD.CD AB² = BC.BD AC² = BC.DC AD² = BD.CD