JEE Main 2020: If α and β be two roots of the equation x²-64x+256=0. Then the value of (α³/β⁵)^1/8

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Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/ Q) If 𝛼 and 𝛽 be two roots of the equation 𝑥^2−64𝑥+256=0. Then the value of (𝛼^3/𝛽^5 )^(1/8)+(𝛽^3/
If alpha & beta be roots of x^2-64x+256 = 0 then value of || JEE 2020 If alpha & beta be roots of x^2-64x+256 = 0 then value of || JEE 2020
If α and β are two roots of the equation x²-64x+256=0,then the value of(α^3/β^5)^1/8+(β^3/α^5)^1/8 If α and β are two roots of the equation x²-64x+256=0,then the value of(α^3/β^5)^1/8+(β^3/α^5)^1/8
If ∝ and β be two roots of the equation x² – 64x + 256 = 0. Then.. | Quadratic Equations | JEE Math If ∝ and β be two roots of the equation x² – 64x + 256 = 0. Then.. | Quadratic Equations | JEE Math
If α and β be two roots of the equation x2-64x+256=0. Then the (α^3/β^5)^(1/8)+(β^3/α^5 )^(1/8) is If α and β be two roots of the equation x2-64x+256=0. Then the (α^3/β^5)^(1/8)+(β^3/α^5 )^(1/8) is
If α and β be two roots of the equation x^2-64 x+256=0. Then the value of (α^3/β^5)^1 / 8+(β^3/α^... If α and β be two roots of the equation x^2-64 x+256=0. Then the value of (α^3/β^5)^1 / 8+(β^3/α^...
If α and β be two roots of the equation x^2 – 64x + 256 =0. Then the value of (α^3/β^5)^(1/8) + (β^3 If α and β be two roots of the equation x^2 – 64x + 256 =0. Then the value of (α^3/β^5)^(1/8) + (β^3
Let α and β be the roots of the equation x^2+(2i-1) = 0. Then, the value of |α^8+β^8| is equal... Let α and β be the roots of the equation x^2+(2i-1) = 0. Then, the value of |α^8+β^8| is equal...