Math solution of. log x/y-z=log y/z-x=log z/x-y, show that xyz=1

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If logx/(y-z) = logy/(z-x) = logz/(x-y) then prove that xyz = 1 | IITJEE Foundation Maths If logx/(y-z) = logy/(z-x) = logz/(x-y) then prove that xyz = 1 | IITJEE Foundation Maths
If x, y, z are positive real numbers prove that (yz)^(logy-logz)*(zx)^(logz-logx)*(xy)^(logx-logy)=1 If x, y, z are positive real numbers prove that (yz)^(logy-logz)*(zx)^(logz-logx)*(xy)^(logx-logy)=1
Tn 11th maths exercise 2.12 question 10/If log x/y-z= log y/z-x=log z/x-y then prove that xyz=1 Tn 11th maths exercise 2.12 question 10/If log x/y-z= log y/z-x=log z/x-y then prove that xyz=1
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If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1` If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1`
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If x, y, z are positive real numbers then prove that yz^(logy - logz) * zx^(logz - logx) * xy^(logx If x, y, z are positive real numbers then prove that yz^(logy - logz) * zx^(logz - logx) * xy^(logx
Show that : (yz)^(logy-logz)×(zx)^(logz-logx)×(xy)^(logx-logy) = 1 Show that : (yz)^(logy-logz)×(zx)^(logz-logx)×(xy)^(logx-logy) = 1