If `tantheta=a/b` ,then `bcos2theta+asin2theta` is equal to (a) `a` (b) `b` (c) `a/b` (d) `b/a`

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If `tantheta=(a)/(b)`, then `bcos2theta+asin2theta` is equal to If `tantheta=(a)/(b)`, then `bcos2theta+asin2theta` is equal to
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