If ∑_(r=0)^5▒(_ ^11)C_(2r+1) /(2r+2)= m/n , gcd ( m, n) = 1 , then m – n is equal to

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If sigma r=0 to 5 11C(2r+1)/2r+2 = m/n, gcd(n,n)=1, then n-n is equal to If sigma r=0 to 5 11C(2r+1)/2r+2 = m/n, gcd(n,n)=1, then n-n is equal to
If sigma r=0 to 5 11C(2r+1) /2r+2 = m/n, gcd(m,n)=1, then m-n = ,#iitjee2025 If sigma r=0 to 5 11C(2r+1) /2r+2 = m/n, gcd(m,n)=1, then m-n = ,#iitjee2025
If ∑ 11 C 2r+1/ 2r+2 = m/n , gcd(m, n) = 1, then m – n is equal to_____ If ∑ 11 C 2r+1/ 2r+2 = m/n , gcd(m, n) = 1, then m – n is equal to_____
If ∑r=0 to 5 (11C(2r+1))/(2r+2) = m/n ,gcd(m, n) =1 , then m−n is equal to If ∑r=0 to 5 (11C(2r+1))/(2r+2) = m/n ,gcd(m, n) =1 , then m−n is equal to
If I did this in 1734 I If I did this in 1734 I'd be World Famous
The value sum r=0 to 5 11C2r+1/2r+2 ( JEE mains 22 Jan 2025 ( morning shift)) The value sum r=0 to 5 11C2r+1/2r+2 ( JEE mains 22 Jan 2025 ( morning shift))
IIT Bombay Lecture Hall | IIT Bombay Motivation | #shorts #ytshorts #iit IIT Bombay Lecture Hall | IIT Bombay Motivation | #shorts #ytshorts #iit
That’s Why IIT,en are So intelligent 😂😂 #iitbombay That’s Why IIT,en are So intelligent 😂😂 #iitbombay