If ba, then the equation (x-a)(x-b)-1=0, has: (A) both roots in [a, b] (B) both roots in (-∞, a) ...

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If \( ba \), then the equation \( (x-a)(x-b)-1=0 \) has (a) both roots in \( (a, b) \) (b) both ... If \( ba \), then the equation \( (x-a)(x-b)-1=0 \) has (a) both roots in \( (a, b) \) (b) both ...
If ba, then the equation (x-a)(x-b)-1=0 has (a) both roots in (a, b) (2000,1 M) (b) both roots in... If ba, then the equation (x-a)(x-b)-1=0 has (a) both roots in (a, b) (2000,1 M) (b) both roots in...
\( ba \), then the equation \( (x-a)(x-b)-1=0 \) (A) both roots in \( [a, b] \) (B) both roots i... \( ba \), then the equation \( (x-a)(x-b)-1=0 \) (A) both roots in \( [a, b] \) (B) both roots i...
If ba, then the equation, (x-a)(x-b)-1=0, has - (A) both roots in [ a, b] (B) both roots in (-∞, ... If ba, then the equation, (x-a)(x-b)-1=0, has - (A) both roots in [ a, b] (B) both roots in (-∞, ...
If bGreater a, then the equation, (x-a)(x-b) – 1 = 0, has a)both roots in [a,b] b)both root If bGreater a, then the equation, (x-a)(x-b) – 1 = 0, has a)both roots in [a,b] b)both root
If b greater than a then the equation (x-a)(x-b)-1=0 has (a). both the roots in [a,b]...... If b greater than a then the equation (x-a)(x-b)-1=0 has (a). both the roots in [a,b]......
#NDA_1_2012,If one of the roots of the equation x²+ax-b=0 is 1,then what is (a-b) equal to#trending #NDA_1_2012,If one of the roots of the equation x²+ax-b=0 is 1,then what is (a-b) equal to#trending
"If `b gt a ,` then the equation `(x-a)(x-b)-1=0` has (2000,1M) both roots in `(a , b)` both roots "If `b gt a ,` then the equation `(x-a)(x-b)-1=0` has (2000,1M) both roots in `(a , b)` both roots