Let f(x) be twice differentiablesuchthat `f''(x)=-f(x), f' (x) = g(x)`, where `f' (x) and f '

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Let f be a twice differentiable function such that f′(x)=−f(x) and f′(x)=g(x), h(x)=[f(x)]2+[g(x)]^2

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Taking Derivative of f(f(x)), TWICE (feat. Chain Rule)