`int_0^(pi/2) cos^2x/(sinx+cosx)dx=1/sqrt2(log(sqrt2+1))`

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Math Fun: Integral Math Fun: Integral
Show that ∫(x→0,π/2)sin2x/(sinx + cosx) = (1/√2)log ( √2+1) Integration 12th Important Question Show that ∫(x→0,π/2)sin2x/(sinx + cosx) = (1/√2)log ( √2+1) Integration 12th Important Question
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Show that integration of 0 to pi/2 sin^2x/sinx+cosx dx =1/root2 log(root2+1) #IIT JEE, Show that integration of 0 to pi/2 sin^2x/sinx+cosx dx =1/root2 log(root2+1) #IIT JEE,
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