If log a/b + log b/a = log (a+b) then..

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Why log(ab) = log(a) + log(b)? Explained Simply Why log(ab) = log(a) + log(b)? Explained Simply
If `log a+b = 1/2(loga+logb) `then the value of `a/b+b/a` If `log a+b = 1/2(loga+logb) `then the value of `a/b+b/a`
If log (a+b/3) = log a + log b/2 find a/b + b/a If log (a+b/3) = log a + log b/2 find a/b + b/a
Mixed: Does log(A/B)=logA-logB. If log(A+B)=logA+logB, how much is A? Mixed: Does log(A/B)=logA-logB. If log(A+B)=logA+logB, how much is A?
If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b` If `log((a+b)/2)=1/2(loga+logb),s h o w t h a t(a+b)/2=sqrt(a b)anda^2+b^2=2a b`
Prove that loga(b)*logb(a)=1 Prove that loga(b)*logb(a)=1
log(a/b)=loga-logb || ln(a/b)=lna-lnb Proof of Logarithm Rule log(a/b)=loga-logb || ln(a/b)=lna-lnb Proof of Logarithm Rule
"If `log\ a/b+log\ b/a=log(a+b),` thena. `a+b=1`b. `a-b=1`c. `a=b`d. `a^2-b^2=1`" "If `log\ a/b+log\ b/a=log(a+b),` thena. `a+b=1`b. `a-b=1`c. `a=b`d. `a^2-b^2=1`"