(a2 + b2 + c2)p2 – 2(ab + bc + cd) p + (b2 + c2 + d2) ≤ 0, then show that a, b, c and dare in G.P.

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25. If a, b, c and d are in G.P. show that(a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 . 25. If a, b, c and d are in G.P. show that(a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 .
If a,b,c,d & p are distinct real numbers such that(a2+b2+c2)p2−2(ab+bc+cd)p+(b2+c2+d2)≤0then a,b,c&d If a,b,c,d & p are distinct real numbers such that(a2+b2+c2)p2−2(ab+bc+cd)p+(b2+c2+d2)≤0then a,b,c&d
If a,b,c,d and p are different real numbers such that: (a^2 + b^2 + c^2)p^2 - 2(ab + bc + cd)p Ex 23 If a,b,c,d and p are different real numbers such that: (a^2 + b^2 + c^2)p^2 - 2(ab + bc + cd)p Ex 23
If a, b, c, d and p are different real numbers such that:(a^2 + b^2 + c^2) p^2 – 2 (ab + bc + cd) p If a, b, c, d and p are different real numbers such that:(a^2 + b^2 + c^2) p^2 – 2 (ab + bc + cd) p
If \\(a, b, c, d\\) and \\(p\\) are distinct real numbers such that a2+b2+c2p2-2(ab+bc+cd)p+b2+c.... If \\(a, b, c, d\\) and \\(p\\) are distinct real numbers such that a2+b2+c2p2-2(ab+bc+cd)p+b2+c....
If a, b, c and d are in G.P. show that . (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 If a, b, c and d are in G.P. show that . (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2
If a, b, c and d are in G.P. show that (a^2 + b^2 + c^2)(b^2 + c^2 + d^2) = (ab + bc + cd)^2. If a, b, c and d are in G.P. show that (a^2 + b^2 + c^2)(b^2 + c^2 + d^2) = (ab + bc + cd)^2.
#Formula (a+b)²=a²+b²+2ab #solution #Formula (a+b)²=a²+b²+2ab #solution