Let ∑_k=1^10 f(a+k)=16(2^10-1), where the function f satisfies f(x+y)=f(x) f(y) for all natural n...

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Let ∑_k=1^10 f(a+k)=16(2^10-1), where the function f satisfies f(x+y)=f(x) f(y) for all natural n... Let ∑_k=1^10 f(a+k)=16(2^10-1), where the function f satisfies f(x+y)=f(x) f(y) for all natural n...
Let ∑_k=1^10 f(a+k)=16(2^10-1), where the function f satisfies f(x+y)=f(x) f(y) for all natural n... Let ∑_k=1^10 f(a+k)=16(2^10-1), where the function f satisfies f(x+y)=f(x) f(y) for all natural n...
XIIRELAOQ098 _ Let ∑_(k=1)^10▒f(a + k) = 16(210-1), where the function f satisfies f(x + y) XIIRELAOQ098 _ Let ∑_(k=1)^10▒f(a + k) = 16(210-1), where the function f satisfies f(x + y)
Let `sum_(k=1)^(10)f(a+k)=16(2^(10)-1),` where the function f satisfies `f(x+y)=f(x)f(y)` Let `sum_(k=1)^(10)f(a+k)=16(2^(10)-1),` where the function f satisfies `f(x+y)=f(x)f(y)`
Find the natural no. a for which ∑f(a+k) =16(2^n-1),where f satisfies f(x+y)=f(x).f(y) and f(1)=2. Find the natural no. a for which ∑f(a+k) =16(2^n-1),where f satisfies f(x+y)=f(x).f(y) and f(1)=2.
Let ∑(k=1)^10f(a+k) = 16(210-1) Where f(x+y) = f(x).f(y) ∀ natural numbers x, y and f(1)=2,then a =? Let ∑(k=1)^10f(a+k) = 16(210-1) Where f(x+y) = f(x).f(y) ∀ natural numbers x, y and f(1)=2,then a =?
Summation Formulas You Need to Know #Shorts #math #maths #mathematics Summation Formulas You Need to Know #Shorts #math #maths #mathematics
The natural number `a` for which `Sigma(k=1- gtn)f(a+k)=16(2^n-1)` where the function `f` satis... The natural number `a` for which `Sigma(k=1- gtn)f(a+k)=16(2^n-1)` where the function `f` satis...