integrate 2 log sinx minus log sin2x from p to pie upon 2 wrt x

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∫ (log (sin x)) dx = ∫ (log (cos x)) dx = -π/2 log x ∫ (log (sin x)) dx = ∫ (log (cos x)) dx = -π/2 log x
integrate 0 to pi/2 integrate 0 to pi/2 '2log(sinx)-log(sin(2x))' dx || `int_(0)^((pi)/(2))(2log sin x- log sin 2x)dx`
Integration of log sinx from 0 to pi/2 | 0 to pi/2 log sinx integration Integration of log sinx from 0 to pi/2 | 0 to pi/2 log sinx integration