Let \(g(x)=f(x)+f(1-x)\) and \(f^{\prime \prime}(x)>0, x \in(0,1)\). If \(\mathrm{g}\) is dec....

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let g(x) = 1+x-[x] and f(x)= -1; 0; 1 where [x] denotes the greatest integer less than then f(g(x))= let g(x) = 1+x-[x] and f(x)= -1; 0; 1 where [x] denotes the greatest integer less than then f(g(x))=
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