Show that (a+b+c)[a^2+b^2+c^2-ab-bc-ca] = a^3+b^3+c^3-3abc || Verify identity | #mathsclass9 |

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a3 + b3 + c3 - 3abc = ( a + b + c).(a2 + b2 + c2 - ab - bc - ca) a3 + b3 + c3 - 3abc = ( a + b + c).(a2 + b2 + c2 - ab - bc - ca)
यदि a^(3) + b^(3) + c^(3) - 3abc = P(a^(2) + b^(2) + c^(2) - ab - bc - ca) तो P का मान लिखिए। |... यदि a^(3) + b^(3) + c^(3) - 3abc = P(a^(2) + b^(2) + c^(2) - ab - bc - ca) तो P का मान लिखिए। |...
PROOF a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac) PROOF a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)
Prove that a³ + b³ + c³ - 3abc = 1/2(a + b + c) {(a-b)² + (b-c)² + (c-a)²)} Prove that a³ + b³ + c³ - 3abc = 1/2(a + b + c) {(a-b)² + (b-c)² + (c-a)²)}
To prove a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ac) class 9th To prove a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ac) class 9th
#Proving_Identity :-a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca) #Proving_Identity :-a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca ) prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca )
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