100mL of 10%(w/V) NaOH added with 100mL of 10%(w/V) HCl find the nature of resultant solution

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`100mL` of `10% NaOH(w/V)` is added to `100 mL` of `10% HCI(w/V)`. The nature of resultant sol `100mL` of `10% NaOH(w/V)` is added to `100 mL` of `10% HCI(w/V)`. The nature of resultant sol
100mL of 10% NaOH(w/V) is added to 100 mL of 10% HCI(w/V). The nature of resultant solution is :... 100mL of 10% NaOH(w/V) is added to 100 mL of 10% HCI(w/V). The nature of resultant solution is :...
`100mL` of `10% NaOH(w/V)` is added to `100 mL` of `10% HCI(w/V)`. The nature of resultant solut... `100mL` of `10% NaOH(w/V)` is added to `100 mL` of `10% HCI(w/V)`. The nature of resultant solut...
100  mL of 10 %NaOH(w / V) is added to 100  mL of 10 %HCl(w / V). The resultant solution becomes:... 100  mL of 10 %NaOH(w / V) is added to 100  mL of 10 %HCl(w / V). The resultant solution becomes:...
100 ml of N/10 NaOH added to 50 ml of N/ 5 HCl the pH of the resulting solution is 100 ml of N/10 NaOH added to 50 ml of N/ 5 HCl the pH of the resulting solution is
100  mL of 10 %NaOH(w / V) is added to 100  mL of 10 %HCl(w / V). The nature of resultant solutio... 100  mL of 10 %NaOH(w / V) is added to 100  mL of 10 %HCl(w / V). The nature of resultant solutio...
sulphuric acid #shorts sulphuric acid #shorts
Following solutions were prepared by mixing different volumes of NaOH and HCl of different conc. Following solutions were prepared by mixing different volumes of NaOH and HCl of different conc.