sslc important question || in triangle ABC angle ABC =90 , BD Perpendicular to AC If BD = 8cm , AD

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SSLC MCQ29.In the given figure ∠ABC=90. BD ⊥ AC. If AB=6cm, BC=8cm, CA=10cm then the length of AD

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SSLC MCQ 27. In the given figure ∆ABC ∼ ∆DEF and ∠ABC=∠DEF = 60 then the length of AC is

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In triangle ABC ,angle ABC=90^@ and BD bot AC. If AD = 4 cm and CD =5 cm, then BD is equal to:\n...