A secant PAB is drawn from an external point P to the circle with the centre at O, intersecting #ssc

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A secant PAB is drawn from an external point P to the circle with centre O, intersecting it at A... A secant PAB is drawn from an external point P to the circle with centre O, intersecting it at A...
From a point P outside a circle, PAB is a secant and PT is a tangent to the circle, where A, B and From a point P outside a circle, PAB is a secant and PT is a tangent to the circle, where A, B and
Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy Proof : PA x PB = PT^2 | Tangents to a circle | Odiya Geometry Class X| Khan Academy
Prove that “the length of tangents drawn to a circle from an external point are equal”.#sslc2026 Prove that “the length of tangents drawn to a circle from an external point are equal”.#sslc2026