Ques-32- Prove that :tanθ/1-cotθ + cotθ/1-tanθ = 1+tanθ+cotθ = secθ.cosecθ+1...

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(1+〖tan〗^2 A)/(1+〖cot〗^2 A) = ((1-tanθ)/(1-cotθ))2 = tan2θ (1+〖tan〗^2 A)/(1+〖cot〗^2 A) = ((1-tanθ)/(1-cotθ))2 = tan2θ
cos12 - sin78 cos12 - sin78
sin(90-θ)=? sin(90-θ)=?
`(cottheta)/(cottheta-cot3theta) + tantheta/(tantheta-tan3theta)` is equal to `(cottheta)/(cottheta-cot3theta) + tantheta/(tantheta-tan3theta)` is equal to
Question no.5(iii) || Trigonometric identities || Exercise - 8.4 || NCERT || Class 10 Question no.5(iii) || Trigonometric identities || Exercise - 8.4 || NCERT || Class 10
tan theta / 1 - cot theta + cot theta divided by 1 minus 10 theta equal to 1 + secant theta into cos tan theta / 1 - cot theta + cot theta divided by 1 minus 10 theta equal to 1 + secant theta into cos