The value of function f(x) = 1+x + ∫_1^x▒(〖ln〗^2 t+2lnt)dt where f^' (x) vanishes is:

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Find the value of the function `f(x)=1+x+int_1^x((lnt)^2+2lnt) dt` where `f Find the value of the function `f(x)=1+x+int_1^x((lnt)^2+2lnt) dt` where `f'(x)` vanishes
Let F(x) = f(x) + f(1/x), where f(x) = ∫_1^x▒(log t)/(1+t) dt. Then F(e) equals a)1/2 b)0 c)1 d)2 Let F(x) = f(x) + f(1/x), where f(x) = ∫_1^x▒(log t)/(1+t) dt. Then F(e) equals a)1/2 b)0 c)1 d)2
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