a+ar+ar²+.....upto n terms = a(rⁿ - 1) / r-1 | Mathematical Induction @EAG

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By MI Prove that a+ar+ar²+....ar^(n-1)=a((r^n)-1)/(r-1) By MI Prove that a+ar+ar²+....ar^(n-1)=a((r^n)-1)/(r-1)
Prove by the principle of Mathematical induction |a + ar + ar^2 + …. + ar^(n-1) = a(r^n -1)/(r-1) Prove by the principle of Mathematical induction |a + ar + ar^2 + …. + ar^(n-1) = a(r^n -1)/(r-1)
Mathematical Induction: Prove that a + a.r + a.r^2 + a.r^3 + ... + a.r^(n-1) = a (r^n-1)/(r-1) Mathematical Induction: Prove that a + a.r + a.r^2 + a.r^3 + ... + a.r^(n-1) = a (r^n-1)/(r-1)
Show that a+ar+ar^2+......upto n terms=a(r^n -1) / (r-1) Show that a+ar+ar^2+......upto n terms=a(r^n -1) / (r-1)
MATHEMATICAL INDUCTION | Q_9 | EDUTAINMENT ONLINE MATHEMATICAL INDUCTION | Q_9 | EDUTAINMENT ONLINE
Proof by Mathematical induction, ∑r^i = (r^(n+1)-1)/(r-1) for r≠0,r ≠1,n∈N. Summation Proof by Mathematical induction, ∑r^i = (r^(n+1)-1)/(r-1) for r≠0,r ≠1,n∈N. Summation
Mathematical Induction a+ar+ar^2+...+ar^(n-1)=a(r^n - 1)/(r-1) for all n greater than or equal to 1 Mathematical Induction a+ar+ar^2+...+ar^(n-1)=a(r^n - 1)/(r-1) for all n greater than or equal to 1
Mathematical Induction || To Prove that || a+ar+ar^2+....+ar^n-1=a(1-r^n)/1-r, if r≠1 Mathematical Induction || To Prove that || a+ar+ar^2+....+ar^n-1=a(1-r^n)/1-r, if r≠1