If f : A to B , g : B to C are two bijective functions then show that (g o f)^(–1) = f^(–1) o g^(–1)

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If f and g are two bijections; then gof is a bijection and `(gof)^-1 = f^-1 o g^-1` If f and g are two bijections; then gof is a bijection and `(gof)^-1 = f^-1 o g^-1`
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