DISCRETE PROBABILITY:Proof that E(aX+b)=aE(X)+b VCE METHODS #vce #mathsmethods

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For any constant a and b, E[aX+b]=aE[X]+b and E[aX-b]=aE[X]-b (Discrete) For any constant a and b, E[aX+b]=aE[X]+b and E[aX-b]=aE[X]-b (Discrete)
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