Prove Sin(B+2C) +Sin(C+2A)+ Sin(A+2B) = Sin(A-B)/2.Sin(B-C)/2.Sin(C-A)/2

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If A+B+C=180° then prove that: sin(B+2C)+sin(C+2A)+sin(A+2B) = 4sin(B-C)/2.sin(C-A)/2.sin(A-B)/2. If A+B+C=180° then prove that: sin(B+2C)+sin(C+2A)+sin(A+2B) = 4sin(B-C)/2.sin(C-A)/2.sin(A-B)/2.
Proof of Sin²A+Sin²B–Sin²C=2SinA.SinB.CosC. Proof of Sin²A+Sin²B–Sin²C=2SinA.SinB.CosC.
If A+B+C=180 degree, sin^2A-sin^2B+sin^2C=2sinA.cosB.sinC If A+B+C=180 degree, sin^2A-sin^2B+sin^2C=2sinA.cosB.sinC
`sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin((B-C)/2)sin((C-A)/2)sin((A-B)/2` `sin(B+2C)+sin(C+2A)+sin(A+2B)=4sin((B-C)/2)sin((C-A)/2)sin((A-B)/2`
12b) If A+B+C=πᶜ, prove that sin(B+ 2C)+sin(C+2A)+sin(A+2B) = 4sin(A-B)/2. sin(B-C)/2.sin(C-A)/2 12b) If A+B+C=πᶜ, prove that sin(B+ 2C)+sin(C+2A)+sin(A+2B) = 4sin(A-B)/2. sin(B-C)/2.sin(C-A)/2
Sin 2A+ Sin 2B+ Sin 2C = 4 Sin A Sin B Sin C Sin 2A+ Sin 2B+ Sin 2C = 4 Sin A Sin B Sin C
Prove (sin2A + sin2B + sin2C )/(sinA + sinB + sinC ) = 8 sin(A/2) sin(B/2) sin(C/2) Prove (sin2A + sin2B + sin2C )/(sinA + sinB + sinC ) = 8 sin(A/2) sin(B/2) sin(C/2)
What does sine actually mean? What does sine actually mean?