2 right triangle ABC&DBC drwn on same base& hypotuse BC. AC intrsct BD at P, prove AP x PC = BP x DP

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Show that : (i) ∆AMC ≅ ∆BMD (ii) ∠DBC = 90° (iii) ∆DBC ≅ ∆ACB (iv) CM = 1/2AB #triangles Show that : (i) ∆AMC ≅ ∆BMD (ii) ∠DBC = 90° (iii) ∆DBC ≅ ∆ACB (iv) CM = 1/2AB #triangles