In the given figure, Angle Q is greater than Angle R, M is point on QR, P is the Bisector of QPR.

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In the given figure, \( \mathrm{PS}=\mathrm{QR} \) and \( \angle \m... In the given figure, \( \mathrm{PS}=\mathrm{QR} \) and \( \angle \m...
Class 9 Maths ,In figure ,PS is the bisector of ∠QPR and PT⊥QR Show that TPS= 1/2 (∠Q-∠R). Class 9 Maths ,In figure ,PS is the bisector of ∠QPR and PT⊥QR Show that TPS= 1/2 (∠Q-∠R).
PS is the bisector of angle QPR and PT is perpendicular to QR. Show that ∠TPS=1/2 (∠Q-∠R) PS is the bisector of angle QPR and PT is perpendicular to QR. Show that ∠TPS=1/2 (∠Q-∠R)
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