let a1=b1=1 and an=an−1+(n−1),bn=bn−1+an−1,∀n≥2.If S=10∑n−1bn2n and T= 8∑n−1n2n−1,then 27(2S−T) is

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Let a1=b1=1&an=a(n-1) +(n-1), bn=b(n—1)+a(n-1), if S=sigma n=1 to 10 bn/2^n&T=sigma n=1to8 n/2(n-1),

Let a1 = b1 =1 and an = an-1 + (n-1), bn = bn-1 +an-1 ......... JEE Mains 2023, Jan 29

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