If |■(a-b-c&2a&2a@2b&b-c-a&2b@2c&2c&c-a-b)|= (a+b+c) (x+a+b+c)

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Show that:det [[a - b - c, 2a, 2a], [2b, b - c - a, 2b], [2c, 2c, c - a - b]] = (a + b + c) ^ 3 Show that:det [[a - b - c, 2a, 2a], [2b, b - c - a, 2b], [2c, 2c, c - a - b]] = (a + b + c) ^ 3
If |(a-b-c&2a&2a@2b&b-c-a&2b@2c&2c&c-a-b)|=(a+b+c) 〖(a+a+b+c)〗^2,x≠0 and a + b + c≠0 , then x is If |(a-b-c&2a&2a@2b&b-c-a&2b@2c&2c&c-a-b)|=(a+b+c) 〖(a+a+b+c)〗^2,x≠0 and a + b + c≠0 , then x is
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