In the given figure AD is perpendicular to BC then prove that AB²+CD²=BD²+AC² | class 10 maths

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In the given figure, AD is perpendicular to BC, prove that AB² + CD² = BD² + AC² In the given figure, AD is perpendicular to BC, prove that AB² + CD² = BD² + AC²
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prove that AB²+CD²=BD²+AC² prove that AB²+CD²=BD²+AC²
in the given figure AD is perpendicular to BC. Prove that AB2+CD2=BD2+AC2#cbseclass10maths in the given figure AD is perpendicular to BC. Prove that AB2+CD2=BD2+AC2#cbseclass10maths
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Theorem based upon Pythagoras theorem -- Vol 1/2 (ACsquared=ABsquared+BCsquared+2BC*BD) Theorem based upon Pythagoras theorem -- Vol 1/2 (ACsquared=ABsquared+BCsquared+2BC*BD)
In the given figure, if AD perpendicular BC , prove that AB2 + CD2 = BD2+ AC2 In the given figure, if AD perpendicular BC , prove that AB2 + CD2 = BD2+ AC2
In the given figure, ∠BCA = 90° and AD ⊥ BC, then: In the given figure, ∠BCA = 90° and AD ⊥ BC, then: