If x=7+4√3 and xy=1 then (1/x²)+(1/y²)=? #class9 #rationalisation

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if x=7 + 4√3 and xy=1 then 1/x^2 +1/y^2= if x=7 + 4√3 and xy=1 then 1/x^2 +1/y^2=
If x=7+4√3 and xy=1 then find 1/x²+1/y² If x=7+4√3 and xy=1 then find 1/x²+1/y²
"If `x=7+4sqrt(3)\ \ a n d\ x y=1`, then `1/(x^2)+1/(y^2)=`64 (b) 134 (c) 194 (d) `1/(49)`" "If `x=7+4sqrt(3)\ \ a n d\ x y=1`, then `1/(x^2)+1/(y^2)=`64 (b) 134 (c) 194 (d) `1/(49)`"
If x=7+4 √(3) and x y=1, then 1/x^2+1/y^2= (a) 64 (b) 134 (c) 194 (d) 1 / 49 If x=7+4 √(3) and x y=1, then 1/x^2+1/y^2= (a) 64 (b) 134 (c) 194 (d) 1 / 49
if x = 7+4rooot3 and xy =1 then 1/x^2 +1/y^2=? if x = 7+4rooot3 and xy =1 then 1/x^2 +1/y^2=?
If x=1/7+4√3 and y=1/7-4√3 then the value of 5x^2-7xy-5y^2 / If x=1/7+4 root 3 and y=1/7-4 root 3 If x=1/7+4√3 and y=1/7-4√3 then the value of 5x^2-7xy-5y^2 / If x=1/7+4 root 3 and y=1/7-4 root 3
X=9+4√5, XY=1, THEN 1/X^2 +1/Y^2| Competitive Maths| X=9+4√5, XY=1, THEN 1/X^2 +1/Y^2| Competitive Maths|
If x = 7 + 4√3 and xy = 1, then 1/(x^2) + 1/(y^2) = ?| Algebra & Rationalise | Concept Clarification If x = 7 + 4√3 and xy = 1, then 1/(x^2) + 1/(y^2) = ?| Algebra & Rationalise | Concept Clarification