In the given Fig., DEFG is a square and ∠BAC=90°. Prove that (i) ΔAGF~ΔDBG (ii) ΔAGF~ΔEFG (iii) ΔDBG

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Target - 95+ | Math | DEFG is Square and Angle BAC = 90° | Show that DE^2 = BD * EC Target - 95+ | Math | DEFG is Square and Angle BAC = 90° | Show that DE^2 = BD * EC
DEFG is a square and ∠BAC=90 show that DE²=BD×EC #triangle #class10 DEFG is a square and ∠BAC=90 show that DE²=BD×EC #triangle #class10