Find the number of divisors of the number `2^5 3^5 5^3 7^3` of the form `(4n+1), n in N uu {0}`

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Number of divisors of `(2^2).(3^3).(5^3).(7^5)` of the form `4n+1, n in N` is: Number of divisors of `(2^2).(3^3).(5^3).(7^5)` of the form `4n+1, n in N` is:
find the number of divisors of (2^2)*(3^3)*(5^3)*(7^5) which are of the form 4n+1. find the number of divisors of (2^2)*(3^3)*(5^3)*(7^5) which are of the form 4n+1.
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Total number of divisors of `N=2^(5)*3^(4)*5^(10)*7^(6)` that are of the form `4n+2,n ge 1`, Total number of divisors of `N=2^(5)*3^(4)*5^(10)*7^(6)` that are of the form `4n+2,n ge 1`,
The number of divisors of the natural number N where `N = 2^5 x3^5 x5^2x7^3` of the form `4n The number of divisors of the natural number N where `N = 2^5 x3^5 x5^2x7^3` of the form `4n
Total number of divisors of `n = 3^5. 5^7. 7^9` that are in the form of `4lambda + 1; lamda g Total number of divisors of `n = 3^5. 5^7. 7^9` that are in the form of `4lambda + 1; lamda g
Total number of divisors of N=3^5· 5^7· 7^9 that are of the form 4 n+1, n ≥ 0 is equal to (a) 15 ... Total number of divisors of N=3^5· 5^7· 7^9 that are of the form 4 n+1, n ≥ 0 is equal to (a) 15 ...