If `a_1, a_2, a_3,.....a_n` are in H.P. and `a_1 a_2+a_2 a_3+a_3 a_4+.......a_(n-1) a_n=ka_1

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If `a_1, a_2, a_3,.....a_n` are in H.P. and `a_1 a_2+a_2 a_3+a_3 a_4+.......a_(n-1) a_n=ka_1 If `a_1, a_2, a_3,.....a_n` are in H.P. and `a_1 a_2+a_2 a_3+a_3 a_4+.......a_(n-1) a_n=ka_1
prove that ((1+a1+a1^2 )(1+a2+a2^2 )(1+a3+a3^2 )…⋅(1+an+an^2 ))/(a1β‹…a2β‹…a3..…an )β‰₯ 3^n prove that ((1+a1+a1^2 )(1+a2+a2^2 )(1+a3+a3^2 )…⋅(1+an+an^2 ))/(a1β‹…a2β‹…a3..…an )β‰₯ 3^n
If `a_1,a_2,a_3,a_4` are in H.P. then `1/(a_1 a_4) sum_(r=1)^3 a_r a_(r+1)` is a root of If `a_1,a_2,a_3,a_4` are in H.P. then `1/(a_1 a_4) sum_(r=1)^3 a_r a_(r+1)` is a root of
MATH OLYMPIAD | EVALLUATE : 1/π‘Ž_1 +1/π‘Ž_2 +1/π‘Ž_3 +…+1/π‘Ž_20 𝑖𝑓 π‘Ž_𝑛=√(1+(1+1/𝑛)^2 )+√(1+(1βˆ’1/𝑛)^2 ) MATH OLYMPIAD | EVALLUATE : 1/π‘Ž_1 +1/π‘Ž_2 +1/π‘Ž_3 +…+1/π‘Ž_20 𝑖𝑓 π‘Ž_𝑛=√(1+(1+1/𝑛)^2 )+√(1+(1βˆ’1/𝑛)^2 )
JEE MAINS 2018 If `a_1,a_2,...a_n` are in H.P then the expression `a_1a_2+a_2a_3+....+a_ (n-1)a... JEE MAINS 2018 If `a_1,a_2,...a_n` are in H.P then the expression `a_1a_2+a_2a_3+....+a_ (n-1)a...
If a_1,a_2,….,a_n are in H.P., then the expression a_1 a_2+a_2 a_3+β‹―+a_(n-1) a_n is equal to If a_1,a_2,….,a_n are in H.P., then the expression a_1 a_2+a_2 a_3+β‹―+a_(n-1) a_n is equal to
Q) Let π‘Ž_1,π‘Ž_2,π‘Ž_3,….be an A.P. If βˆ‘_(π‘Ÿ=1)^βˆžβ€Šπ‘Ž_π‘Ÿ/2^π‘Ÿ =4, then 4a_2 is equal to ____ #jee #maths Q) Let π‘Ž_1,π‘Ž_2,π‘Ž_3,….be an A.P. If βˆ‘_(π‘Ÿ=1)^βˆžβ€Šπ‘Ž_π‘Ÿ/2^π‘Ÿ =4, then 4a_2 is equal to ____ #jee #maths
If `a_1,a_2,……….a_n` are in H.P, then the expression `a_1a_2+a_2a_3+…+a_(n-1)a_n` is equal to If `a_1,a_2,……….a_n` are in H.P, then the expression `a_1a_2+a_2a_3+…+a_(n-1)a_n` is equal to