`int_(0)^(pi//2)(2logcosx-logsin2x)\ dx=-(pi)/(2)log2`

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सिद्ध कीजिए कि - int_(0)^((pi)/(2))(2logsinx-logsin2x)dx=-(pi)/(2)log2. | 12 | निश्चित समाकलन |... सिद्ध कीजिए कि - int_(0)^((pi)/(2))(2logsinx-logsin2x)dx=-(pi)/(2)log2. | 12 | निश्चित समाकलन |...
Evaluate integrate 0 to pi /2 [log(sin x) - log(2cos x)] dx from 0 to pi/2 | ∫ log(sinx) -log(2cosx) Evaluate integrate 0 to pi /2 [log(sin x) - log(2cos x)] dx from 0 to pi/2 | ∫ log(sinx) -log(2cosx)
`int_0^(pi/2)(2logcosx-logsin2x) dx` `int_0^(pi/2)(2logcosx-logsin2x) dx`
Improper Integral || Show that ∫_0^(π/2)log(sinx)dx converges to -π/2 log2 || Real Analysis Improper Integral || Show that ∫_0^(π/2)log(sinx)dx converges to -π/2 log2 || Real Analysis
Prove that `int_(0)^(pi//2)(2logsinx-logsin2x)dx=(pi)/(2)(log2)`. Prove that `int_(0)^(pi//2)(2logsinx-logsin2x)dx=(pi)/(2)(log2)`.
Show that the integral 0 to pi/2 logsinxdx=-1/2 π log2 | Definite integral Show that the integral 0 to pi/2 logsinxdx=-1/2 π log2 | Definite integral
Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2` Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2`