If `cosalpha+cosbeta=0=sinalpha+sinbeta`. Prove that `cos2alpha+cos2beta=-2cos(alpha+beta)`

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If `cosalpha+cosbeta=0=sinalpha+sinbeta`, then prove that If `cosalpha+cosbeta=0=sinalpha+sinbeta`, then prove that
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if cosalpha+cosbeta +cosgamma =0=sinalpha +sinbeta+singamma then sin^2alpha+sin^2beta+sin^2gamma=3/2 if cosalpha+cosbeta +cosgamma =0=sinalpha +sinbeta+singamma then sin^2alpha+sin^2beta+sin^2gamma=3/2