The function 𝑓:[0,3]→[1,29], defined by 𝑓(𝑥)=2𝑥^3−15𝑥^2+36𝑥+1 is

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The function f:[0,3]→[1,29], defined by f(x)=2x^3-15x^2+36x+1, The function f:[0,3]→[1,29], defined by f(x)=2x^3-15x^2+36x+1,
The function f:[0,3] →[1,29], defined by f(x)=2 x^3-15 x^2+36 x+1, is (2012) (a) one-one a... The function f:[0,3] →[1,29], defined by f(x)=2 x^3-15 x^2+36 x+1, is (2012) (a) one-one a...
The function `f: [0,3] to [1,29],` defined by `f(x)=2x^(3)-15x^(2)+36x +1,` is The function `f: [0,3] to [1,29],` defined by `f(x)=2x^(3)-15x^(2)+36x +1,` is
The function f:[0,3] → [1,29], defined by f(x)=2x 3 −15x 2 +36x+1, is #iitjee #calculus #function The function f:[0,3] → [1,29], defined by f(x)=2x 3 −15x 2 +36x+1, is #iitjee #calculus #function
Let f : [0,3] → A be defined by f(x) = 2x^3 -15x^2 + 36x + 7 and g : [0,∞)→ B be defined by g(x) Let f : [0,3] → A be defined by f(x) = 2x^3 -15x^2 + 36x + 7 and g : [0,∞)→ B be defined by g(x)
The function f : [0, 3] → [1, 29], defined by f(x) = 2x³-15x² + 36x + 1, is one-one ,onto ?|Function The function f : [0, 3] → [1, 29], defined by f(x) = 2x³-15x² + 36x + 1, is one-one ,onto ?|Function
Let f:[0,3]→A be defined by f(x)=2x^3-15x^2+36x+7 and g:[0,∞)→B be defined by g(x)=x^2025/x^2025+1. Let f:[0,3]→A be defined by f(x)=2x^3-15x^2+36x+7 and g:[0,∞)→B be defined by g(x)=x^2025/x^2025+1.
Let f : [0,3] → A be defined by f(x) = 2x^3-15x^2+36x+7 and g : [0,∞)→ B be defined by g(x) = x^202 Let f : [0,3] → A be defined by f(x) = 2x^3-15x^2+36x+7 and g : [0,∞)→ B be defined by g(x) = x^202