Why Logarithm of a Number to Its Own Base is 1

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log (1+1/a) base 2 + log (1+1/b) base 2 + log (1+1/c) base 2 = 2 then a + b + c log (1+1/a) base 2 + log (1+1/b) base 2 + log (1+1/c) base 2 = 2 then a + b + c