a,b) R (c,d) ⟺ ad(b+c)= bc(a+d). Check whether R is an equivalence relation on N×N

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N be set of natural numbers and R be the relation on N×N defined by (a,b) R (c,d)⇔ad(b+c) = bc(a+d) N be set of natural numbers and R be the relation on N×N defined by (a,b) R (c,d)⇔ad(b+c) = bc(a+d)
R be a relation on NxN defined by (a,b) R (c,d) = ad(b+c) = bc(a+d), Check weather R is an equi R be a relation on NxN defined by (a,b) R (c,d) = ad(b+c) = bc(a+d), Check weather R is an equi
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show that the relation R in the set N × N defined by (a, b) R (c, d) iff ad = bc is the equivalence show that the relation R in the set N × N defined by (a, b) R (c, d) iff ad = bc is the equivalence
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#18. Let N be the set of all natural numbers and let R be a relation on NxN as (a,b)R(c,d)⇔ad=bc•••• #18. Let N be the set of all natural numbers and let R be a relation on NxN as (a,b)R(c,d)⇔ad=bc••••
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How to prove an Equivalence Relation?ρ={((a,b)(c,d))∈(ℕ⨯ℕ)⨯(ℕ⨯ℕ); ad(b+c)=bc(a+d)}||Rimpa Singha Roy How to prove an Equivalence Relation?ρ={((a,b)(c,d))∈(ℕ⨯ℕ)⨯(ℕ⨯ℕ); ad(b+c)=bc(a+d)}||Rimpa Singha Roy