The number of integral values of k for which the equation7 cos x + 5 sin x = 2k+1 has a solution is:

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The number of integral values of k, for which the equation 7 cos⁡〖x+5 sin⁡〖x=2k+1〗 〗 has a solution, The number of integral values of k, for which the equation 7 cos⁡〖x+5 sin⁡〖x=2k+1〗 〗 has a solution,
Find the number of integral values of k for which the equation 7 cos x+5 sin x=2k+1 has at least... Find the number of integral values of k for which the equation 7 cos x+5 sin x=2k+1 has at least...
Find the no. of integral values of k for which the equation `7cosx+5sinx=2k+1` has atleast one Find the no. of integral values of k for which the equation `7cosx+5sinx=2k+1` has atleast one
The number of integral value of \( k \) for which the equation \( 7 \cos x+5 \sin x=2 k+1 \) has... The number of integral value of \( k \) for which the equation \( 7 \cos x+5 \sin x=2 k+1 \) has...
[IIT 2002] Find integral values of k for which 7cosx + 5sinx = 2k + 1 has a solution. [IIT 2002] Find integral values of k for which 7cosx + 5sinx = 2k + 1 has a solution.
The number of integral value of k for which the equation 7 cos x + 5 sin x = 2k +1 has a solution... The number of integral value of k for which the equation 7 cos x + 5 sin x = 2k +1 has a solution...
The number of integral values of k for which the equation 7 cos x+5 sin x=2 k+1 has a solution, i... The number of integral values of k for which the equation 7 cos x+5 sin x=2 k+1 has a solution, i...
∫dx/(1 + tan²⁰¹⁷(x)) [0, π/2]. Answer ≠ 0 😅 MIT Integration Bee 2017 (Question 18, Qualifying Exam) ∫dx/(1 + tan²⁰¹⁷(x)) [0, π/2]. Answer ≠ 0 😅 MIT Integration Bee 2017 (Question 18, Qualifying Exam)