In the given figure, OA . OB = OC . OD. Show that ∠A = ∠C and ∠B = ∠D.

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In the figure, OA.OB=OC.OD. Show that ∟A=∟C and ∟B=∟D In the figure, OA.OB=OC.OD. Show that ∟A=∟C and ∟B=∟D
In the given figure, OA .OB = OC.OD, show that: ∠A = ∠C and ∠B = ∠D. In the given figure, OA .OB = OC.OD, show that: ∠A = ∠C and ∠B = ∠D.
Example 6 : In Fig. 6.31, OA . OB = OC . OD. Show that  A =  C and  B =  D. Example 6 : In Fig. 6.31, OA . OB = OC . OD. Show that  A =  C and  B =  D.
SAS ,SSS similarity criteria | In given Fig OA.OB=OC.OD .Show that ∠ A = ∠ C , ∠ B = ∠ D | triangles SAS ,SSS similarity criteria | In given Fig OA.OB=OC.OD .Show that ∠ A = ∠ C , ∠ B = ∠ D | triangles
in the given fig OA . OB = OC. OD show that angle A = angle C and angle B = angle A@MathsTransporter in the given fig OA . OB = OC. OD show that angle A = angle C and angle B = angle A@MathsTransporter
In the given figure, OA.OB = OC.OD, show that : ∠A = ∠C and ∠B = ∠D. In the given figure, OA.OB = OC.OD, show that : ∠A = ∠C and ∠B = ∠D.
Class 10 Triangles || Example 6 || In Fig. 6.31, OA . OB = OC . OD. Show that ∠A = ∠C and ∠B=∠D. Class 10 Triangles || Example 6 || In Fig. 6.31, OA . OB = OC . OD. Show that ∠A = ∠C and ∠B=∠D.
In the Figure OA. OB = OC. OD,Show that ∆A = ∆C and ∆B = ∆D |Class 10 Maths #maths In the Figure OA. OB = OC. OD,Show that ∆A = ∆C and ∆B = ∆D |Class 10 Maths #maths