If `(n+1)! =12 xx [(n-1)!]`, find the value of n.

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If (n+1) !=12 ×[(n-1) !], find the value of n If (n+1) !=12 ×[(n-1) !], find the value of n
Prove that: \[ \frac{n !}{(n-r) !}=n(n-1)(n-2) \ldots(n-(r-1)) \] Prove that: \[ \frac{n !}{(n-r) !}=n(n-1)(n-2) \ldots(n-(r-1)) \]
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