If cot θ= 7/8, evaluate (i) (1+ sinθ)(1- sinθ)/(1+cosθ )(1- cosθ ), (ii) cot²θ, class 10maths NCERT

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If cotθ=7/8 find i) (1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ) ii) cot²θ If cotθ=7/8 find i) (1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ) ii) cot²θ
If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ. If cot θ = 7/8, evaluate : (i) (1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ), (ii) Cot²θ.
7. If cot θ =7/8 evaluate : (i) (1 sin )(1 sin ),(1 cos )(1 cos )+ θ − θ+ θ − θ(ii) cot2 θ 7. If cot θ =7/8 evaluate : (i) (1 sin )(1 sin ),(1 cos )(1 cos )+ θ − θ+ θ − θ(ii) cot2 θ
If Cot theta equal to 7 by 8 Evaluate (i) (1+sin θ) (1-sin θ)/(1+cos θ)(1-cos θ) (ii) Cot²θ If Cot theta equal to 7 by 8 Evaluate (i) (1+sin θ) (1-sin θ)/(1+cos θ)(1-cos θ) (ii) Cot²θ
7. Given Cot θ=7/8 evaluate (i)(1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ) (ii)(1+Sinθ)/Cosθ | Class 10 | Gyan 7. Given Cot θ=7/8 evaluate (i)(1+Sinθ)(1-Sinθ)/(1+Cosθ)(1-Cosθ) (ii)(1+Sinθ)/Cosθ | Class 10 | Gyan
Class 10 chapter 8 trigonometry If cot θ=7/8,evaluate:(i)(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)(ii) cot2θ Class 10 chapter 8 trigonometry If cot θ=7/8,evaluate:(i)(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)(ii) cot2θ
Q. 7 : If cot θ = 7/8 , evaluate : (i) ((1 + sinθ )(1+ sin θ))/((1+cosθ)(1-cosθ))... Q. 7 : If cot θ = 7/8 , evaluate : (i) ((1 + sinθ )(1+ sin θ))/((1+cosθ)(1-cosθ))...
If cot theta is equal to 7 by 8 evaluate | Trigonometry If cot theta is equal to 7 by 8 evaluate | Trigonometry