Theory of equations :solve if 2+i√3 is a root of x^4-4x^2+8x+35=0

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Solve the equation x^4 - 4x^2 + 8x + 35 = 0 having one root as 2 + i*sqrt(3). Solve the equation x^4 - 4x^2 + 8x + 35 = 0 having one root as 2 + i*sqrt(3).
Solve the equation x⁴ - 4x² + 8x + 35 = 0, given that 2 + i root 3 is a root @EAG Solve the equation x⁴ - 4x² + 8x + 35 = 0, given that 2 + i root 3 is a root @EAG
Solve the equation x^4-4x^2+8x+35=0 given that one of roots is 2+sqrt(-3) | 12 | COMPLEX NUMBERS... Solve the equation x^4-4x^2+8x+35=0 given that one of roots is 2+sqrt(-3) | 12 | COMPLEX NUMBERS...
Part 10 || Solve x⁴-4x²+8x + 35 = 0, given that 2+ i√3 is a root Part 10 || Solve x⁴-4x²+8x + 35 = 0, given that 2+ i√3 is a root
Quadratic Equations | Solve by factoring | Free Math Videos Quadratic Equations | Solve by factoring | Free Math Videos
Solve `x^4-4x^2+8x+35=0` ,given that `2+isqrt(3) ` is a root. |Class 12 MATH | Doubtnut Solve `x^4-4x^2+8x+35=0` ,given that `2+isqrt(3) ` is a root. |Class 12 MATH | Doubtnut
Solve x^4 - 4x^2 + 8x +35=0, given one 2 + i √3 is one root. Solve x^4 - 4x^2 + 8x +35=0, given one 2 + i √3 is one root.
solve x^4-4x^2+8x+35=0;given 2+i√3 is a root of given equation solve x^4-4x^2+8x+35=0;given 2+i√3 is a root of given equation