If `x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab`, then `(xyz)/(xy+yz+zx)` is equal to

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If `x=1+log_a bc, y=1+log_b ca, z=1+log_c ab` then prove that `xyz=xy+yz+zx` If `x=1+log_a bc, y=1+log_b ca, z=1+log_c ab` then prove that `xyz=xy+yz+zx`
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If x = 1 + loga bc, y = 1 + logb ca, z = 1 + logc ab, then xyzxy+yz+zx is equal to.... If x = 1 + loga bc, y = 1 + logb ca, z = 1 + logc ab, then xyzxy+yz+zx is equal to....
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If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A... If a = 1 + log_(x) yz, b = 1 + log_(y) zx, c =1 + log_(z) xy, then ab+bc+ca = | 12 | SEQUENCES A...