IF A = SUM OF 1/nCr , THEN VALUE OF SUM OF r/nCr

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If an= summation 1/nCr then summation r/nCr is equal to (a)(n-1)an (b)nan (c)1/2nan (d)NOT | BT PYQ🔥 If an= summation 1/nCr then summation r/nCr is equal to (a)(n-1)an (b)nan (c)1/2nan (d)NOT | BT PYQ🔥
BINOMIAL: FIND (1)IF a=sum 1/(nCr),then find sum r/(nCr) (2) double sum of (i+j).nCi.nCj BINOMIAL: FIND (1)IF a=sum 1/(nCr),then find sum r/(nCr) (2) double sum of (i+j).nCi.nCj
JEE Delight: Binomial series reversing technique: if summation 1/nCr=a find summation r/nCr JEE Delight: Binomial series reversing technique: if summation 1/nCr=a find summation r/nCr
If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n` If `a_n=sum(r=0)^n 1/^nC_r, then sum _(r=0^n r/^nC_r` equals (A) `(n-1)a_n` (B) `na_n` (C) `1/2na_n`
Sum of Series 2 - Int x nCr Sum of Series 2 - Int x nCr
Sum of Series 1 - Int x nCr Sum of Series 1 - Int x nCr
Binomial theorem: PQ11 Find summation (-1)^rnCr/r+2Cr? Binomial theorem: PQ11 Find summation (-1)^rnCr/r+2Cr?
`sum_(r=0)^n (-1)^r .^nC_r (1+rln10)/(1+ln10^n)^r` `sum_(r=0)^n (-1)^r .^nC_r (1+rln10)/(1+ln10^n)^r`