Jee Mains2024If alpha denotes number of solutions of|1-i|=2^x and beta=|z|/argz where z= pi/4(1+i)^4

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If α denotes the number of solutions of |1-i|^x=2^x and β=((|z|)/(arg⁡(z))), where z=π/4(1+i)^4 If α denotes the number of solutions of |1-i|^x=2^x and β=((|z|)/(arg⁡(z))), where z=π/4(1+i)^4
If alpha denotes the number of solutions of |1-i|^x =2^x ..... | jee mains 2024 maths solution If alpha denotes the number of solutions of |1-i|^x =2^x ..... | jee mains 2024 maths solution
If alpha denotes the number of solutions of |1-i|^x=2^x and beta =(|z|/arg(z)),where Z= 1/2(1+i)^4.. If alpha denotes the number of solutions of |1-i|^x=2^x and beta =(|z|/arg(z)),where Z= 1/2(1+i)^4..
If α denotes the number of solutions of |1-i|ˣ = 2ˣ and β = (|z|/arg(z)), where z = π/4(1+i)⁴(1-√ π If α denotes the number of solutions of |1-i|ˣ = 2ˣ and β = (|z|/arg(z)), where z = π/4(1+i)⁴(1-√ π
Only 1% of Know This Trick | Maths Olympiad | (x+1)^4 + (x+5)^4 = 32 Only 1% of Know This Trick | Maths Olympiad | (x+1)^4 + (x+5)^4 = 32
π=4 π=4
Why is π = 0 in Complex Number System? Why is π = 0 in Complex Number System?
#If z=α+iβ,|z+2| = z + 4(1+i), then α+β & αβ are the roots of the eqn #jeemains2023 #complexnumbers #If z=α+iβ,|z+2| = z + 4(1+i), then α+β & αβ are the roots of the eqn #jeemains2023 #complexnumbers