If a+b+c=0, then one root of |[ a-x c b; c b-x a; b a c-x ]|=0 is (1) x=1 (2) x=2 (3)...

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If a+b+c=0 and det (a-x c b, c b-x a , b a c-x)=) then x = If a+b+c=0 and det (a-x c b, c b-x a , b a c-x)=) then x =
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